$\lim_{x\to0}\left(\frac{\left(4^x-2^x\right)}{\left(1-3^x\right)}\right)$
$\sqrt[3]{75\:m^3}z^6$
$-3x-8\left(x+1\right)$
$\left(5x-3\right)\le12$
$\left(4mn-6\right)^2$
$-6x^2+4lx-2l^2$
$\left(-1\right)+1-\left(-1\right)$
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