$\frac{2}{x-1}+\frac{4}{2-x}=0$
$\left(x^5+6\right)^2$
$a-2a+3a$
$\lim_{x\to\infty}\left(\frac{x^3-2x+1}{x^3+3x^2+7}\right)^{2x}$
$\frac{x^5\:-\:32}{x\:-\:2}$
$\int\:\frac{sec\left(u\right)}{tan\left(u\right)}du$
$\sqrt{25x^2+50xy+25y^2}$
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