$\frac{9-x^2}{5x-10}$
$\frac{6^{10}}{4^4}$
$6x^2+5x-1=0$
$\int\frac{4x^2+9x-1\:}{x^3+2x^2-x-2}dx$
$\frac{xy}{2\:\:}\:\:y\left(1\right)=1$
$\int\frac{1}{5x+5}dx$
$-6\left(12-15\right)+2^3$
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