$\left(2x\right)\left(x^4-3x^2+5x-1\right)$

$9q^2-\frac{2}{3}\left(3q-7\right)+5q^2$

$12x-14=-2x^2$

$\left(2+3\right)^{\frac{1}{v}}$

$\frac{d^3}{dx^3}\left(\frac{5}{8}x^{-2}+\frac{4}{3}x^3+\frac{2}{3}x^4+\frac{1}{10}x^{-3}\right)$

$\left(+5\right)+\left(-4\right)\cdot\left(+6\right)$

$cot\left(x\right)+2=0$