$\frac{d^2u}{dt^2}+\frac{du}{dt}=6u+5e^{2t}$
$\frac{xy^3}{-5xy}$
$\left(3a^2\:b\right)^3\:\left(2a^3\:b\right)$
$a^2-2a^3+3a^4-4a^5+6a^6$
$\left(5-12\right)\left(12-5\right)$
$p\left(x\right)=x^2+\left(a+3\right)x^3+2x+a$
$2x^2-9x-1$
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