$\frac{3}{2\sqrt{3}t\sqrt{2}}$
$3y^3-2y^2+3-y^3+5$
$x2\:-\:\:1\:0x\:+\:24$
$\frac{-2x}{x^2-49}+\frac{10}{x-7}=\frac{1}{x+7}$
$tgx\left(1-ctgx\right)+ctgx\left(1-tg^2x\right)+\left(1-cos^2x\right)$
$7x\:>\:56$
$7^2\cdot7^5\cdot2^2$
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