$\int\frac{6x}{\sqrt[3]{10-9x^2}}dx$
$\frac{d}{dy}\left(-6x^3y^2+3e^{2x}y^2-y^3=0\right)$
$18x^2-39x+20$
$\left(4x+4\right)=\frac{dy}{dx}-4y$
$-168+36\infty$
$x\left(2\right)-3x+9$
$\sqrt[4]{0.18}$
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