$\int\frac{1}{x^2-14x+49}dx$

$a3x-10=21x+2b$

$\left(-321\right)-\left(-28\right)$

$\frac{sec\left(x\right)tan\left(x\right)}{\sin\left(x\right)}=sec^2\left(x\right)$

$\frac{\left(1-p\right)^2}{p}=11$

$\int9cos^3\left(x\right)dx$

$\sin\left(-x\right)-\cos\left(-x\right)=\frac{1}{\sin\left(x\right)^2\cdot\cos\left(x\right)^2}$