$3.01\cdot0.11$

$\frac{\left(3\cdot x+1\right)}{7}-\frac{\left(2-4\cdot x\right)}{3}\ge\frac{\left(-5\cdot x-4\right)}{14}+\frac{\left(7\cdot x\right)}{6}$

$3^2\:-\:b^2$

$\left(-1\right)\left(32\right)$

$\frac{3}{5}m^{2}-2m+10m^{2}$

$x^3+2^2-4x-8$

$0-\left(\frac{\left(-1\right)\left(1.3\right)}{12.78584918-\left(-1\right)}\right)$