$\left(\sqrt{2}e^x\right)^2$
$16-5x\ge3x$
$\frac{120}{107.6}$
$\frac{sec^2x-1}{tanx}=tanx$
$\lim_{x\to\infty}x^3e^{x^{-2}}$
$\frac{x^2+6x+12}{x+2}<\:1$
$\left(\frac{4}{5}x+3\right)\left(\frac{1}{5}x-\frac{2}{5}\right)$
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