$\left(\sec\left(a\right)^2\right)-\left(\tan\left(b\right)^2\right)$
$12x^3+21x^2-8x-14$
$\int_0^1\left(\frac{1}{x\cdot\ln\left(x\right)^2}\right)dx$
$4y-20y+25$
$-3a^2b+3ab$
$-1.301.\frac{46}{12}$
$b+2.5r=15.25$
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