$\int y^{10}dy$
$x+8=18.48$
$15\cdot16$
$-\sin^2\left(x^2\right)-\cos^2\left(x^2\right)$
$sin^4x=\frac{3}{8}+\frac{1}{8}\left(cos\left(4x\right)\right)-\frac{1}{2}\left(cos\left(2x\right)\right)$
$16-10x^2+16$
$\int\frac{x+4}{\left(2x+3\right)^{-2}}dx$
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