$\left(2+\sqrt{y}\right)\left(2x-\sqrt{y}\right)$
$\tan^2x+\sqrt{3}\tan\left(x\right)=0$
$\left(4a-7b\right)^3$
$1+x^2+lnx\cdot\left(1-x^2\right)=0$
$\frac{\left(15\right)\left(4\right)\left(-8\right)}{\left(-3\right)\left(-4\right)}$
$\left(-3\right)\left(-2\right)\left(7\right)\left(-5\right)$
$5x^2-x-2$
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