−4⋅mn+0-4\cdot mn+0−4⋅mn+0
(x2−2x5)2\left(x^2-\frac{2x}{5}\right)^2(x2−52x)2
dydx=3x2+2x4y2−5\frac{dy}{dx}=\frac{3x^2+2x}{4y^2-5}dxdy=4y2−53x2+2x
limx→0(xx−1−1ln(x))\lim_{x\to0}\left(\frac{x}{x-1}-\frac{1}{ln\left(x\right)}\right)x→0lim(x−1x−ln(x)1)
∫02(2(z2+1)3)dz\int_0^2\left(\frac{2}{\left(z^2+1\right)^3}\right)dz∫02((z2+1)32)dz
(1−3x4)−53\left(1-\frac{3x}{4}\right)^{-\frac{5}{3}}(1−43x)−35
3x2+3x−603x^2+3x-603x2+3x−60
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