$x^2+196x$
$ln\left(2x+1\right)+ln\left(x-1\right)-2lnx=0$
$12,53\:+\:5,402\:+\:2,1$
$\left(5x^2-3y\right)\left(2x^2+y\right)$
$\frac{5.60}{12}$
$-\frac{1}{3}\ln\left(y^3-1\right)=\ln\left(x\right)$
$\frac{dy}{dx}=-7x^6+1$
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