$\frac{dy^2}{dx^2}+4x=1$
$\int x\left(x^2-1\right)^2\:dx$
$-4\:x\:-9$
$\frac{1}{1-\:sin\left(x\right)}+\frac{1}{1+\sin\:\left(x\right)}=1$
$\left(4z-3\right)\left(4z-7\right)$
$\left(x-y\right)\cdot\left(z^2\right)$
$f\left(x\right)=\frac{x^{2}-x-2}{x-8}$
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