$\frac{d}{dx}\left(\frac{10}{x}+3xy+sin\left(y\right)=10\right)$
$x^2-1.2x-2.25$
$\frac{4x^3-12x^2+2x+11}{2x-4}$
$\frac{-3-12-5}{10}$
$( 4 x ^ { 3 } - \frac { 1 } { 6 } ) ^ { 3 }$
$\frac{dy}{dt}=-\frac{y}{t}+2\:$
$4.86\cdot10^5$
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