∫16+3xxdx\int\frac{\sqrt{16+3x}}{x}dx∫x16+3xdx
3b−12<8+b3b-12<8+b3b−12<8+b
+−8+−−2+\sqrt{-8}+-\sqrt{-2}+−8+−−2
∫(2x2x2−1)dx\int\left(2x^2\sqrt{x^2-1}\right)dx∫(2x2x2−1)dx
limx→3(x3−26x−3)\lim_{x\to3}\left(\frac{x^3-26}{x-3}\right)x→3lim(x−3x3−26)
2x5−8x2+42x^5-8x^2+42x5−8x2+4
16x+15x2−1516x+15x^2-1516x+15x2−15
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