$\left(1+x+y\right)^2$
$\left(-\frac{4}{9}x^4+\frac{3}{7}y\right)^2$
$\frac{6^{-4}}{\left(6^6\right)^{-1}}$
$r^6-8$
$\left[4-3\left(m+n\right)\right]\left[4+3\left(m+n\right)\right]$
$x\sqrt{4}-y\sqrt{4}\frac{x}{y}$
$g\left(x\right)=\tan\left(4x^3-x\right)$
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