5x2+12x+3=05x^2+12x+3=05x2+12x+3=0
f(m)=(m+3)3m−1f\left(m\right)=\frac{\left(m+3\right)^3}{m-1}f(m)=m−1(m+3)3
8m3+2162x+6\frac{8m^3+216}{2x+6}2x+68m3+216
4x2−12x4x^2-12x4x2−12x
(x−3)4(x−2)\left(x-3\right)^4\left(x-2\right)(x−3)4(x−2)
(3x+2xy)2\left(3x+2xy\right)^2(3x+2xy)2
(−15)+12+7(−12)\left(-15\right)+12+7\left(-12\right)(−15)+12+7(−12)
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