$\int\frac{y^2}{\left(x^2+4\right)}dx$
$3^x-3^x\cdot\:81$
$\frac{d^2}{dx^2}\left(4x-9y=36\right)$
$\frac{y\left(x\right)}{x}+\frac{y\left(x\right)^3}{x^3}$
$-3\:\cdot\:5+4\:\cdot\:-2$
$553x\:+\:168y\:=\:z$
$\left(11\cdot t-1\right)^2$
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