$\left(5\right)^3-3\left(5\right)^2-4\left(5\right)-30$
$r^2-12r+27=\left(r-9\right)\left(r-3\right)$
$2-2\left(x+6\right)<2+x$
$2\left(qx\:+8\right)$
$\frac{x^3-x^2+x-1}{x^3}$
$\left(6x^6y^4\right)^{-3}$
$\sqrt[3]{81x^2y^4}$
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