$\left(\frac{2^4m.2m^5}{16sm^2}\right)^3$
$x^9+x^8$
$2x^2-3x+1=0$
$\int\left(yx+y\right)y^xdy$
$f\left(x\right)=\cot\left(\left(x^3+x^2-x\right)^2\right)$
$f\left(x\right)=-\frac{1}{2}x^{4}-\frac{2}{3}x^{3}+12x^{2}+5$
$4x^2\:=\:15\:-\:17x$
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