$$\left(2a+3\right)x\left(3a-2\right)x\left(4a+1\right)$$

$$\frac{9}{\left(3x+2^2\right)}$$

$$\left(4a^0\right)^4$$

$$7m+6m^2$$

$$2 h + 4 h - 7$$

$$\frac { d y } { d x } = x e ^ { y }$$

$$\lim_{x\to0}\left(\frac{x\:+\:ln\left(b\right)}{x\:-\:ln\left(b\right)}\right)^x$$