$( 4 + 5 m ) ^ { 3 }$
$x^2+8x-33=0$
$108:-18$
$\frac{\sin^3\left(x\right)+1}{\sin\left(x\right)+1}=\sin^2\left(x\right)-\sin\left(x\right)+1$
$\frac { 6 x ^ { 3 } - 2 x ^ { 3 } } { x - y }$
$\frac{x-3\left(x-9\right)}{x^2}$
$4x^{2}+4x-7$
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