$\int\left(\left(x-1\right)e^x\right)dx$
$\frac{x^3-3x^2+x+3}{x-5}$
$8x\:-\:9y\:+12\:+2y\:+9x\:-25$
$\left(4x^3-5y\right)^3$
$2,4\cdot2,4$
$2a^5b^4c-3a^4b^3c^2+\frac{1}{3}a^3b^2c^3$
$\frac{\left(4a^{-1}b^{-2}\right)^2}{\left(a^{-6}b^{-4}\right)^{-3}}$
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