$\left(2x^2+5\right)\left(3x-2\right)$
$x+18x$
$\int\frac{5x-1}{x^2+1}dx$
$\int\sec^2\left(w\right)tan^4\left(w\right)dw$
$\frac{dy}{dx}=\frac{y^{\frac{3}{5}}}{x^{\frac{1}{7}}}$
$\frac{dy}{dx}=\frac{-10y}{5+2x}$
$3x^{2y-24xy+48}$
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