$\left(\frac{x^2}{3}\right)^2$

$-\frac{5}{3}\cdot\frac{9}{5}$

$\int\frac{1+yx}{\left(1-x\right)^2}dx$

$-4^6$

$\left(\left(x^{\left(\frac{1}{3}\right)}\right)-\left(y^{\left(-\frac{1}{3}\right)}\right)\right)^3$

$2u-11\le\:\:5u+6$

$\left(-z\right)^2\left(z\right)^{-3}\left(z\right)^{-4}$