$\frac{\sec^6\left(x\right)-\tan^6\left(x\right)}{\sec^2\left(x\right)\cdot\tan\left(x\right)}$
$-12+34-22+14-10-12-6+7+56$
$\left(a^4+8\right)\left(a^2-1\right)$
$\left(7\right)\left(5\right)\left(-5\right)$
$x+7=10$
$5x+2x+2y$
$\frac{-9^3}{\frac{x}{3}}$
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