$\frac{81a^6-100b^8}{9^3+10b^4}$
$-2-\left(-14\right)$
$\lim_{x\to0}\left(\frac{x^2-6x}{x^2-4}\right)$
$\left(5-xy\right)^2$
$16-x^2=9$
$4x^2-12x+9=10$
$\left(x^2-y^2\right)-\left(x-y\right)^2$
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