$\sin x=1-\cos x$
$\frac{1}{ts^2+s}$
$5x+8<2x-6$
$\sqrt[2]{4\:a^2}b\:^4$
$x^5+3x^2-2x$
$\lim_{x\to-2}\left(x\left(3x-1\right)\left(x+2\right)\right)$
$\frac{1}{2-2}$
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