$1-16a^4b^6c^2$
$\frac{9x^2}{3x^3}$
$\int\:\:\frac{sec\:y\:tan\:y}{2+\:sec\:y\:}dy$
$\left(a+b-c\right)\left(a-b-3c\right)$
$5^2+3^2\cdot4$
$6x-5\ge9x+1$
$\frac{\frac{\pi}{4}}{\frac{1}{2}}$
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