$4x^2+x+4$
$\left(4m+6\right)\left(5m+9\right)$
$4\left(1\right)-5\left(-2\right)+2\left(4\right)+8\left(-4\right)$
$\sqrt[3]{x}\cdot\sqrt{x^2}\cdot\sqrt{x^4}$
$2x\:+6\:<4$
$\left(3m-5\right)^2-\left(m+3\right)^2$
$\int arc\cdot cos\left(x\right)dx$
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