$\int\frac{-12}{x+3}dx$
$6x^2+14x+4\ge0$
$m^2+5m-14=0$
$\lim_{x\to0}\left(\frac{\sqrt{x+3}\:-2}{x-1}\right)$
$\ln\left(x-2\right)=\ln\left(2\right)+\ln\left(x-3\right)$
$\left(7m^2-5n\right)^2$
$\int_2^4\left(\sqrt{x^2-8}\right)dx$
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