Simplifying
−x2(2x+1)+1x2-x^2\left(2x+1\right)+1x^2−x2(2x+1)+1x2
(y2 + 3 x y) dx = (4 x2 + x y) dy\left(y^2\:+\:3\:x\:y\right)\:\:dx\:=\:\left(4\:x^2\:+\:x\:y\right)\:\:dy(y2+3xy)dx=(4x2+xy)dy
(+20)⋅(−3)(+4)\left(+20\right)\cdot\frac{\left(-3\right)}{\left(+4\right)}(+20)⋅(+4)(−3)
k2−2k+1k^2-2k+1k2−2k+1
x2+y=4x^2+y=4x2+y=4
∫15xdx\int\frac{1}{5x}dx∫5x1dx
(3−3y2)\left(3-3y^2\right)(3−3y2)
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