$$\int\frac{3x}{\sqrt{2x^2-3}}dx$$

$$\lim_{x\to-2}\left(\frac{x^2-4}{x^2+6x+8}\right)$$

$$\infty7$$

$$18-\left[2+\left[9-\left(6-4\right)-5\right]\right]$$

$$\cot\left(x\right)=\csc\left(x\right)$$

$$2x^2-4x+5=6$$

$$-2-3\left(-8\right)$$