$\int x\sqrt{5-x^2}dx$
$2+3+5+4+7+3+5+8$
$\frac{dy}{dx}=2-8y$
$-2.7+\left(-4.9\right)$
$\frac{d}{dx}\frac{x^8cosx}{tanx}$
$\left(1+\cos x\right)\left(1-\cos x\right)=\tan^2x\cos^2x$
$\left(r-2\right)^2\left(r-3\right)^2\left(r-6\right)$
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