$3x-18\:<75$
$\left(3x^2-y^3\right)^2$
$\left(2^{-8}\right)^{-6}$
$75\cdot10$
$\int\frac{x^4}{x^2+441}dx$
$\left(\frac{1}{y}\right)\left(\frac{y^{3}}{1}\right)$
$\left(\frac{-4x}{9x^2-9}\right)^1$
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