$$\left(6ab-4a\right)^3$$

$$\left(+800\right)-\left(-200\right)$$

$$\left(7+x\right)^2+\left(7-x\right)^2=130$$

$$\left(x-3\right)\left(3=x\right)$$

$$\frac{\left(1-p\right)^2}{p}=0.01\:$$

$$\int\left(x^2+2\right)^5\cdot dx$$

$$2,5+0$$