Solve the product 3tan(1)(tan(x)−1)\sqrt{3}\tan\left(1\right)\left(\tan\left(x\right)-1\right)3tan(1)(tan(x)−1)
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dydx=(x−9)y8x2(6y5−y)\frac{dy}{dx}=\frac{\left(x-9\right)y^8}{x^2\left(6y^5-y\right)}dxdy=x2(6y5−y)(x−9)y8
2x+4+8x=32x2+4x\frac{2}{x+4}+\frac{8}{x}=\frac{32}{x^2+4x}x+42+x8=x2+4x32
−4−5+2−1-4-5+2-1−4−5+2−1
64−16x=32x264-16x=32x^264−16x=32x2
−5(2)232-5\left(2\right)^23^2−5(2)232
a2+11aa^2+11aa2+11a
16w2−494w−7\frac{16w^2-49}{4w-7}4w−716w2−49
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