$\sqrt[3]{5^3}$
$\frac{x-1}{x-\frac{1}{x}}$
$\left(2x^3\right)\left(3x^5\right)\left(6x\right)^2$
$9-3a=15$
$2\left(x+y\right)dx+dy=0$
$\left(-9kp\right)^2\cdot\left(-3p^4\right)$
$\sqrt{9x^4}-\cot\left(x\right)$
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