$\lim_{x\to0}\left(\ln\left(\frac{x}{e^x-1}\right)\right)$

$-5j\:+\left(-2j\right)+3$

$\left(\frac{\left(x^2\right)^5}{\left(x^3\right)^2x^4}\right)$

$x^2+6x-72=0$

$f\left(x\right)=\left(x^2-5x+2\right)\left(2x+3\right)$

$\int_0^{\infty}\left(\frac{x}{\sqrt{x^2+1}}\right)dx$

$0.5\left(4m^2+16m+8\right)$