$\left(4-8\right):2-\left(9-12\right):3$
$18\sqrt{4}+47\sqrt{4}$
$y^4+y^3+y^2=0$
$40+-7+33+4$
$\lim_{x\to\infty}\left(\frac{4x^2+7x}{6x^3+2x+8}\right)$
$\left(3x^3-x+12\:\right)\left(x^2-5x+8\right)$
$3x^2+18x-17=0$
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