$a^2-18a+16$
$\int_0^{\infty}\left(\frac{1}{1+x^2}-\frac{3}{3x+1}\right)dx$
$\left(6x^3+4y^5\right)\left(6x^3-4y^5\right)$
$7-2\frac{x^{3}+8}{x+2}$
$x^3-14x^2+57x-72$
$3x^2+3y^2=-6$
$\frac{x^7y^5}{x^3y}$
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