$3x^2+12x+36$
$9\left(-4-10p\right)+9p-4$
$y^3+4^3$
$\:\frac{1}{6n^2}\left(x-4\right)^n$
$=-\sqrt{50x}$
$\frac{2x^5-4x^2}{x^3+7}$
$\left(-8\right)+\left(+5\right)\left(-1\right)$
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