$5x+6<6x+10$
$\frac{dy}{dx}=-2xy=e^{x^2}$
$\frac{dy}{dx}y^2-9x=3$
$\int_0^3\left(\left(3-x\right)^{-6}\right)dx$
$16y^2+64y+4$
$\frac{2}{3}.\frac{3}{1}$
$464 \times 4 + 176 x ^ { 2 } + 121$
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