$\frac{8x^2+6x-20}{4x+9}$
$3\sqrt[3]{64b^3}c^3$
$\frac{x^2+2x-6}{x+3}$
$\left[\left(-49\right)\:-\:\left(-21\right)\right]-\:\left(+12\right)\:$
$\lim_{x\to\infty}\left(\frac{12e^{\ln\:\left(x\right)^{\frac{1}{2}}}}{\sqrt{x}}\right)$
$18a^3-72ab^2$
$d=x^2$
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