1−sin2x⋅1+tan2x=11-\sin^2x\cdot1+\tan^2x=11−sin2x⋅1+tan2x=1
sin4(x)+cos4(x)−1sin2(x).cos2(x)\frac{\sin^4\left(x\right)+\cos^4\left(x\right)-1}{\sin^2\left(x\right).\cos^2\left(x\right)}sin2(x).cos2(x)sin4(x)+cos4(x)−1
3 x 3 x 3 x 33\:x\:3\:x\:3\:x\:33x3x3x3
4tan(x)=5cos(x)4\tan\left(x\right)=5\cos\left(x\right)4tan(x)=5cos(x)
4x2−9y22x−3y\frac{4x^2-9y^2}{2x-3y}2x−3y4x2−9y2
drdq=300200q\frac{dr}{dq}=\frac{300}{\sqrt{200q}}dqdr=200q300
∫cos5(x3)dx\int\cos^5\left(\frac{x}{3}\right)dx∫cos5(3x)dx
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