$3\left(2y+3\right)=6y+9$
$-9\left(x-1\right)$
$5abc\cdot\left(4a^6b^3\right)^2$
$\int_0^1\left(\frac{1-\cos\left(x\right)}{x^4}\right)dx$
$\left(x^8\right)\left(x^{-5}\right)$
$\left(4+x\right)^{-0.5}$
$225a^2-1444b^2$
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