$\sqrt{2}x\sqrt{6}$
$2x-3\le x$
$\lim_{x\to0}\left(\frac{e^{8x}-1}{e^{-8x}-1}\right)$
$x^{2+6x+9}$
$\lim_{x\to\infty}\left(\frac{x+5}{x\ln x}\right)$
$\lim_{x\to\infty}\left(x^2+3x-1\right)$
$14x\:+\:9=22x+1$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!